Question

A bullet of mass bog ,50g
leaves the barrel
of a gun with a velocity of 40 m/s calcetet
the KIE of the bullet​

Answer 1

Correct Question:

A bullet of mass 50g leaves the gun with a velocity of 40 m/s. Find the kinetic energy of bullet.

Answer:

The kinetic energy of the bullet is 40 J.

Step-by-step explanation:

$\boxed{\sf{Kinetic \: Energy} = \frac{1}{2}m {v}^{2} }$

• m = 50 g = 0.05 kg
• v = 40 m/s

$\sf{\longrightarrow} \: K E = \dfrac{1}{2} \times 0.05 \times {(40)}^{2}$

$\sf{\longrightarrow} \: K E = \dfrac{1}{2} \times 0.05 \times 1600$

$\sf{\longrightarrow} \: K E = 0.05\times 800$

$\sf{\longrightarrow} \: K E = 40$

Kinetic Energy of the bullet = 40 J

Therefore, the kinetic energy of the bullet is 40 J.

Answer 2

Answer:

Appropriate Question :-

• A bullet of mass 50 g, leaves the barrel of a gun with a velocity of 40 m/s. Calculate the kinetic energy of the bullet.

Given :-

• A bullet of mass 50 g, leaves the barrel of a gun with a velocity of 40 m/s.

To Find :-

• What is the kinetic energy of the bullet.

Formula Used :-

$\clubsuit$ Kinetic Energy or K.E Formula :

$\longmapsto \sf\boxed{\bold{\pink{Kinetic\: Energy =\: \dfrac{1}{2}mv^2}}}$

where,

• m = Mass
• v = Velocity

Solution :-

First, we have to find convert the mass into kg :

$\implies \sf Mass =\: 50\: g$

$\implies \sf Mass =\: \dfrac{50}{1000}\: \: \bigg\lgroup \bold{\pink{1\: g =\: \dfrac{1}{1000}\: kg}}\bigg \rgroup$

$\implies \sf Mass =\: \dfrac{5\cancel{0}}{100\cancel{0}}\: kg$

$\implies \sf Mass =\: \dfrac{5}{100}\: kg$

$\implies \sf\bold{\purple{Mass =\: 0.05\: kg}}$

Given :

• Mass (m) = 0.05 kg
• Velocity (v) = 40 m/s

According to the question by using the formula we get,

$\dashrightarrow \sf Kinetic\: Energy =\: \dfrac{1}{2} \times 0.05 \times {(40)}^{2}$

$\dashrightarrow \sf Kinetic\: Energy =\: \dfrac{1}{2} \times 0.05 \times 40 \times 40$

$\dashrightarrow \sf Kinetic\: Energy =\: \dfrac{1}{2} \times 0.05 \times 1600$

$\dashrightarrow \sf Kinetic\: Energy =\: \dfrac{1}{\cancel{2}} \times {\cancel{80}}$

$\dashrightarrow \sf Kinetic\: Energy =\: 1 \times 40$

$\dashrightarrow \sf\bold{\red{Kinetic\: Energy =\: 40\: J}}$

$\therefore$ The kinetic energy of the bullet is 40 J.