Question

A bullet of mass m 50gm strikes a sand bag of mass m 5kg hanging from a fixed point with a horizontal velocity vp. if bullet sticks to the bag then after collision

Answer 1

Ratio of final K.E to initial K.E is 10‑4.

Explanation:

Correct statement:

A bullet of mass m 50 g strikes a sand bag of mass m 5 kg hanging from a fixed point with a horizontal velocity vp. if bullet sticks to the bag then after collision the ratio of final and initial kinetic energy of the bullet is?

According to Conservation of Momentum,

mVp = (m+M)V

where

• Mass of the bullet = m
• Vp is the velocity of the bullet before collision

• M is the mass of the sandbag and V is the velocity after the collision

Solution:

0.05 x  vp  = (0.050+5)V

Vp = [5.050/0.05] V = 101 V  

Ratio of final K.E to initial K.E = [0.5mV^2] / [0.5mvp^2] =   10‑4

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