Question

A bullet of mass m fired at 30° to the horizontal leaves the barrel of the gun with a velocity v The bullet hits

Answer 1

I think so the bullet hits with the velocity of 150

Answer 2

Ans: Let v1 be the velocity of bullet after emerging from the target. K.E of the bullet emerging from the target

1/2mv1^2=1/2(1/2mv^2)

v1=v/√2=0.707

This implies that the velocity is more than half of its earlier velocity

Therefore (b),(d),(f) are correct