Question

A bullet of mass m fired with velocity u forming an angle theta with the horizontal and get embedded in a wooden block of same mass m the block is placed on smooth surface the magnitude of horizontal component of impulse is

Answer 1

Answer:By conservation of Momentum principle,

$M_{i} =mu\\M_{f} =(m+M)v$

∴$M_{i} =M_{f} =mu=(m+M)v$

∴$v=\frac{mu}{m+M}$