Question

A bullet of mass 'm' is fired from a rifle of mass M. If v~ be the velocity ofbullet, velocity acquired by
the rifle​

Answer 1

Answer:

using the equation for conservation of linear momentum-

m1u1 +m2u2= m1v1+m2v2

since the gun and the bullet were initially at rest, the left hand side of this equation can be taken as zero ( since u1=v1=0)

so now we get-

m1v1+m2v2=0

taking m2v2 on the other side-

m1v1= -m2v2

here, let us take mass of the gun=M=m1

mass of the bullet=m =m2

velocity of the bullet=v=v2

from the derived equation on substituting values we get-

M(v1)= -mv

v1=. -(mv)/M

therefore the velocity acquired by the rifle is -mv/M