Question

A bullet of mass m is fired horizontally into a large solid sphere of mass m and radius r resting on a smooth horizontal table. The bullet hits the sphere at a height h from the table and sticks to its surface. If the sphere starts rolling without slipping immediately on impact then.

Answer 1

Answer:

i think the answer is already in the web

Explanation:

You are welcome

Answer 2

$\frac{h}{R}= \frac{10m+7M}{5(m+M)}$

Explanation:

By applying the principle of conservation of linear momentum:

V=ωR

$mv_0= (m+M)V$

        = (m+M)V

        = (m+M)ωR

By conservatuion of angular momentum about centre,

$mv_0(h-R)=(\frac{2MR^2}{5}+mR^2)$ω

$(m+M)R\omega (h-R)=(\frac{2MR^2}{5}+mR^2)\omega$

On solving we get,

$\bold {\frac{h}{R}= \frac{10m+7M}{5(m+M)}}$