Question

A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M. If the block rises to height h, then initial velocity v of the bullet must be

Answer 1

You have to use Conservation of Momentum here,
Let ,
mv = (m+M) V
where V is a velocity of block and bullet combined after hit.
Now, when Block rises up the kinetic energy of block converted into potential energy.
so,
1/2 (m+M) V^2 = (m+M)gh
V^2 = 2gh
V = √2gh
so, we get
v = ( (m+M) ×√2gh) / m

Answer 2

The answer is provided in the attachment.

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