Question

a bullet of mass m moving with velocity Vo hits a wooden plank of mass M placed on a horizontal surface the length of the plank is L the bullet experiences a constant resistive force of F inside the block the minimum value of Vo such that it can come out of the plank

Answer 1

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Answer 2

Answer:

The minimum value of  V₀  such that it can come out of the plank is$\sqrt{\frac{-2FL}{M}}$.

Explanation:

mass of bullet = M

the velocity of the bullet = V₀

Length of the plank = L

The force acting inside the plank is constant which is F in opposite to the motion of the bullet.

F = Ma

=> a =$\frac{F}{M}$

acceleration is opposite to the motion of the bullet so

a =  $\frac{-F}{M}$

So, we can use the equation of motion

V² - U² = 2aS . . .(1)

V₀² - 0 =  $\frac{-2FL}{M}$

=> V₀ = $\sqrt{\frac{-2FL}{M}}$

The minimum value of Vo such that it can come out of the plank is V₀ = $\sqrt{\frac{-2FL}{M}}$.