Question

A bullet of mass ‘m1’ moving with a speed ‘x’ strikes a wooden block of mass ‘m2’ and gets embedded in it. The speed of the embedded block will be ? Please answer this correctly. Best answer will be marked as brainliest !

Answer 1

Answer:

The speed will be m2 x.

Explanation:

ACCORDING TO CONSERVATION OF MOMENTUM,

m1u1+m2u2 = (m1+m2)v

So, Here m1=m1     and  m2=m2

               u=x and v=?

So,m1x+m2*0 = (m1+m2)x

    m1x             = m1x + m2x

    m1x-m1x     = m2x

so final answer is M2X

Plz mark as brainliest...

Answer 2

Answer:

M1 x/m2

Explanation: