A bullet of mass ‘m1’ moving with a speed ‘x’ strikes a wooden block of mass ‘m2’ and gets embedded in it. The speed of the embedded block will be ? Please answer this correctly. Best answer will be marked as brainliest !
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Answered by
6
Answer:
The speed will be m2 x.
Explanation:
ACCORDING TO CONSERVATION OF MOMENTUM,
m1u1+m2u2 = (m1+m2)v
So, Here m1=m1 and m2=m2
u=x and v=?
So,m1x+m2*0 = (m1+m2)x
m1x = m1x + m2x
m1x-m1x = m2x
so final answer is M2X
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Answered by
3
Answer:
M1 x/m2
Explanation:
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