Question

a bullet of mass10g is moving with velocity of 400m/s gets embedded in a freely suspended wooden block of 900g. what is velocity acquired by block

Answer 1

m1 = 10g

v1 = 400m/s

m2 = 900g

v2 = ?

m1v1 = (m1 + m2)v2

10 × 400 = (10 + 900)v2

4000 = 910v2

4000/ 910 = v2

v2 = 4.39m/s



Thanks