a bullet of mass20 g moving with a sspeed of 120 m/s hits a thick muddy wall and penetrate into it. it takes 0.03 s to stop in the wall. find the distance
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v= u- at ( because of retardation)
120 = a×0.03 ( intial velocity is 0)
a= 4000 m/s²
also
s= ut + 1/2 at²
s= 1/2 × 4000 × 0.03× 0.03 ( u is 0)
= 1.8 m
v= u- at ( because of retardation)
120 = a×0.03 ( intial velocity is 0)
a= 4000 m/s²
also
s= ut + 1/2 at²
s= 1/2 × 4000 × 0.03× 0.03 ( u is 0)
= 1.8 m
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