Question

A bullet of weight 10gm is fired from a gun of mass 500gm . The gun is recoiled at a velocity 20m/s . Find out the velocity of the bullet. ​

Answer 1

Answer:

Explanation:- hope u understand this.

Answer 2

Given :

• Mass of the bullet = 10 gm = 0.01 kg
• Mass of the gun = 500 gm = 0.5 kg

• Recoil velocity of the gun = - 20 m/s

To find :

• The velocity of the bullet

Solution :

As no external force is acting on the system (bullet + gun ) the total momentum of the system remains conserved .

By applying law of conservation of momentum ,

Initial momentum of the system = Final momentum of the system

Initially the system (gun + bullet) is at rest . Hence , the initial momentum of the system will be zero .

Final momentum of the system = 0

$\implies P_ g + P_ b = 0$

$\implies P_ b= - P_ g$

$\implies m \times u = - M \times V$

$\implies u = -\dfrac { M \times V } {m}$

Now let's substitute the values ,

$\implies u = -\dfrac { 0.5 \times - 20 } {0.01 }$

$\implies\boxed{u = 1000 \:m/s }$

The velocity of the bullet is 1000 m/s .