A bullet on penetrating 30 cm into its target loses its velocity by 50%. What additional distance will it penetrate into the target before it comes to rest?
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The bullet will penetrate to 10 cm
Explanation:
Given data:
S = 30 cm = 30 x 10^-2 m
Loss in velocity = 50%
Equation of motion:
v^2 = u^2 + 2as
Here u^2 / 4 = u^2 + 2a x 30 x 10^-2 ...... (1)
0 = u^2 / 4 + 2a × x ......... (2)
On solving Equations (1) and (2) we get
x = 10 cm
Thus the bullet will penetrate to 10 cm.
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A machine gun fires a bullet of mass 40 g with a velocity 1200 ms.the man holding it,can exert a maximum force of 144 N on the gun.how many bullets can he fire per second at the most?
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