Question

a bullet shot straight up returns to its starting point in 10sec what is the initial speed was
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Answer 1

Answer:

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Answer 2

Answer: c)49m/s

Explanation:

A bullet shot straight upwards returns to its starting point in 10s. What was its initial velocity?

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Use the Linear Motion equation for displacement:

s = ut + 1/2at^2

The displacement (s) of the particle is 0m since it returns to its original position, the time taken (t) is 10s and the acceleration due to gravity acting [downward] on the object is -9.81 m/s^2 [taking the upward direction as positive]. Sub all this into the equation to get:

0 = u(10) + 1/2(-9.81)(10)^2

0 = 10u - 490.5

Now rearrange to get:

490.5 = 10u

And finally take the 10 across to get:

u = 490.5/10

u = 49.05 m/s

u = 49.05 m/s#Mark as brainliest

u = 49.05 m/s#Mark as brainliest#Hope it is helpful

Explanation: PLS MARK ME AS BRAINLIEST