Question

a bullet shot with a velocity 350m/s enters a concrete wall and penetrates a distance of 5m before coming to rest.find the retardation​

Answer 1

Answer:

Explanation:

initial velocity=350m/s

distance moved=5m

final velocity=0 as the bullet comes to rest after moving that 5 m

so we know the basic equation:

v²=u²+2as

as it is retardation a= -a

so (0)²=(350)² -2×a×5

0=122500-10a

10a=122500⇒a=12250m/s²

so the retardation is 12250m/s²

Hope this helps

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