A bullet the f mass 4g is fired from a gun of mass 4kg what is the recoil velocity of gun if the bullet moves with 10m/s
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Answer:
Velocity of recoil = 0.01 m/s
Explanation:
Let's take m1 = 4 gram = 0.004 Kg
m2 = 4 kg
v1 = 10 m/s
v2 =?
According to the law of conservation of momentum,
Total momentum before firing = Total momentum after firing
(Before firing both the rifle and bullet is at rest and so Total momentum before firing is zero)
0 = m1*v1 + m2*v2
0 = 0.004*10 + 4*v2
v2 = -0.01 m/s
(Negative sign indicates that movement of rifle is opposite to bullet)
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