Question

A Bullet to mass 20 g is horizontally fixed with the velocity 150 m/ s from a pistal of mass 2kg . What is the recoil velocity of the pistal

Answer 1

let the mass of bullet br M1 = 0.02 kg
mass of gun be M2 = 2kg
velocity of bullet be V1 = 150m/s
the velocity of gun be V2 = V

by applying conservation of momentum
M1V1 = M2V2
0.02×150 = 2×V
3 = 2×V
-1.5 = V

therefore the recoil velocity of gun will be -1.5m/s because it will move un backward direction after firing the bullet