a bullet train hits a wall with a velocity of 20 metre/second and penetrates it up to a distance of 5 cm . find the deceleration of the bullet in the wall
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Since deceleration is asked ..so ...answer is - 4000 ms ^-2..
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★Hey mate★✋
Here is your answer.
Given that,
The uniform velocity, u = 20m/s
The last velocity, v = 0m/s [The bullet stopped]
The distance, s = 5cm = 0.05 m.
The deceleration, a = ❓
We know, v² = u² - 2as {it is deceleration}
=> 0 = (20)² - 2×a×0.05
=> 0 = 400 - 0.1a
=> 0.1a = 400
=> a = 400\0.1
=> a = 4000 m\s²
So, the deceleration 4000 m\s² and acceleration -4000 m\s².
∆Hope it will help you friend.∆ :)
Here is your answer.
Given that,
The uniform velocity, u = 20m/s
The last velocity, v = 0m/s [The bullet stopped]
The distance, s = 5cm = 0.05 m.
The deceleration, a = ❓
We know, v² = u² - 2as {it is deceleration}
=> 0 = (20)² - 2×a×0.05
=> 0 = 400 - 0.1a
=> 0.1a = 400
=> a = 400\0.1
=> a = 4000 m\s²
So, the deceleration 4000 m\s² and acceleration -4000 m\s².
∆Hope it will help you friend.∆ :)
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