Question

a bullet train is running at the speed of 254 3/11miles/ hour. if the train needs to increase in speed to 315 5/22 miles/ hour. find the no. of mile
s required by the train to travel more in one hour maths question
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Answer 1

Answer:

188830000232125855988888

Answer 2

Given :-

Bullet train runs in a speed of = 254 3/11 miles/hour

Speed needed to be increased = 315 5/22 miles per hour

To Find :-

The number of miles required by the train to travel more in 1 hour.

Solution :-

We know that,

• u = Initial velocity
• v = Final velocity
• a = Acceleration
• t = Time

Given that,

initial speed (u) = 254 3/11 mi/h

Final speed (v) = 315 5/22 mi/h

Time (t) = 1 hour

Using the formula,

$\underline{\boxed{\sf v=u+at}}$

Substituting their values, we get

$\implies \sf 315 \ \dfrac{5}{22} =254 \ \dfrac{3}{11} +a \times 1$

$\implies \sf \dfrac{6935}{22} -\dfrac{2797}{11} =a$

$\implies \sf a=\dfrac{(6935-5594)}{22}$

$= \sf a=\dfrac{1341}{22}$

Using the formula,

$\underline{\boxed{\sf s = ut + \frac{1}{2} \ at^{2} }}$

$\implies \sf 253 \ \dfrac{3}{11} \times 1 + \dfrac{1}{2} \times \dfrac{1341}{22} \times 1^{2}$

$\implies \sf \dfrac{254}{11} +\dfrac{1341}{44}$

$\sf =\dfrac{254 \times 4+1341}{44}$

$\sf =53 \ \dfrac{23}{44}$

Therefore, 53 23/44 miles required by the train to travel more in 1 hour.