Question

A bullet train start from rest and moves with unifrom acc 0.12m/s*2 find its final velocity and distance coverd after 5min​

Answer 1

Answer:

v = u + at

v = 0.12 x 5 x 60

v = 36 m/s

Answer 2

Answer:

u=0

a=0.12

v?

s?

t=300sec

Explanation:

v=ut+at

v=at [u=0]

v=0.12×300

v=36m/s

for s

s=ut+1/2at^2

s=1/2 ×at^2 [u=0!]

s=1/2×0.12×300300

s= 18×300

s=5400 meter or 5.4km