a bullet travelling at 16 m per second particles at tree trunk it comes to rest m travelling a distance of 0.6 M what is the retardation in metre per second square
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Answered by
2
Hello Mate!
Here, v = 0
u = 16 m/s
s = 0.6m
By using third deriviation we know that,
v^2 - u^2 = 2as
0 - 16^2 = 2 × a × 0.6m
-256 = 1.2a
-256 / 1.2 = a
- 213.3 m/s^2 = a
Hope it helps☺!✌
Here, v = 0
u = 16 m/s
s = 0.6m
By using third deriviation we know that,
v^2 - u^2 = 2as
0 - 16^2 = 2 × a × 0.6m
-256 = 1.2a
-256 / 1.2 = a
- 213.3 m/s^2 = a
Hope it helps☺!✌
Answered by
2
hey there
s = 0.6m
v = 0
u = 16m /s
now v square = u square +2as
0 square = 16 square + 2*a * 0.6
0 = 256 + 1.2a
1.2 a = 256
12/10a = 256
a = 256 *10/12
a =213.3
retardation = -213.3m per second square
s = 0.6m
v = 0
u = 16m /s
now v square = u square +2as
0 square = 16 square + 2*a * 0.6
0 = 256 + 1.2a
1.2 a = 256
12/10a = 256
a = 256 *10/12
a =213.3
retardation = -213.3m per second square
Ambadas11:
thanks
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