A bullet travelling at 300 m/ pierces a hole 10 cm. Deep in a block of wood before it comes to rest . Calculate the deceleration of the bullet
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deceleration = a m/sec²
u = 300 m/sec
s = 10 cm = 0.1 m
v = 0
v² = u² + 2 a s
a = (0² - 300²) / (2 * 0.1)
a = - 4,50,000 m/sec²
u = 300 m/sec
s = 10 cm = 0.1 m
v = 0
v² = u² + 2 a s
a = (0² - 300²) / (2 * 0.1)
a = - 4,50,000 m/sec²
kvnmurty:
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u , s, v, a, stands for?
u = initial speed. v = final speed. a = acceleration/deceleration. s = distance travelled... these are usual symbols. so did not mention
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