A bullet travelling with a velocity of 16 m/s pretends a tree and comes to rest in 0.4 m find the time taken during retraction
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2
Answer:
Explanation:
v=0
u=16m/s
s=0.4m
we know
v^2-u^2=2as
0-16^2=2a(0.4)
a=-320m/s^2
Now, for time, we use,
v=u+at
0=16–320×t
-16=-320t
16/320 =t
t=0.05
Answered by
1
Answer:
A bullet travelling with a velocity of 16 m/s pretends a tree and comes to rest in 0.4 m find the time taken during retraction
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