Question

A bullet was thrown vertically upwards from a heigh ,reaches it's maximum height in 4seconds calculate the initial velocity of the bullet and the total distance the bullet travels by the time it reaches the maximum height

Answer 1

Answer:

Explanation:

t=4seconds

during the upward motion

u=unknown

v=0[finally comes to rest at maximum height]

according to newtons law,

v=u+at      a=-10[acting downwards that is against the motion if the bullet and hence taken as negative]

0=u-10*4

u=40ms^-1

now for the upward motion,

v^2-u^2=2as

0-40*40=2*-10*s

s=80m for the upward motion

therefore the total distance covered =2*80m=160m