Question

A bullet weighing 10 g and moving at 300 m/s strikes a 5tkg block of ice. The ice block is sitting on frictionless level surface. The speed of the block after the collision is?

Answer 1

But time isnt mentioned

Answer 2

Answer:

The speed of the block after collision is 60 cm/s.

Explanation:

Given;-

      Mass of bullet, m₁= 10 g

      Mass of ice, m₂= 5kg

                               = 5000 g

Initial velocity of m₁= 300 m/s

Initial velocity of m₂ = 0 (at rest)

We know that, for perfectly inelastic collision, the final common velocity is given by;-

            v = m₁u₁ + m₂u₂ / m₁ + m₂

Putting the given values in the formula, we get;-

             v = 10 × 300 + 5000 × 0/ 5000 + 10

             v = 3000/ 5010

             v = 0.6 m/s

             v = 60 cm/s

Hope it helps! ;-))