a bullet weighing 10 g is moving with velocity of 800m/s strikes a 10 kg block resting on a frictionless surface. the speed of the block after the inelastic collision is approximatly
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Momentum of bullet = 10/100 × 800 = 80kg.m/s
Momentum of block = 101/100 ×0 = 0
total momentum before collision is equal to total momentum after collision
80 = m×v
80 = 10.1 × v
v = 800/101
v = 7.92 m/s
Momentum of block = 101/100 ×0 = 0
total momentum before collision is equal to total momentum after collision
80 = m×v
80 = 10.1 × v
v = 800/101
v = 7.92 m/s
nishil17:
ans is o.8
yes so my answer is right as it was asking approx. then 0.72 = 0.8
yes
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5
0.01*800/0.01+10=vf
vf=0.8
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