Question

a bullet weighing 10 g is moving with velocity of 800m/s strikes a 10 kg block resting on a frictionless surface. the speed of the block after the inelastic collision is approximatly

Answer 1

Momentum of bullet = 10/100 × 800 = 80kg.m/s
Momentum of block = 101/100 ×0 = 0
total momentum before collision is equal to total momentum after collision
80 = m×v
80 = 10.1 × v
v = 800/101
v = 7.92 m/s

Answer 2

0.01*800/0.01+10=vf

vf=0.8