A bullet when fired at a target with a velocity of 100 m/sec penetrates one metre into it . if the bullet is fired at a similar target with a thickness 0.5 metre, then it will emerge from it with avelocity of___ m/s.
Answers
Answered by
30
the first case
a = (v2 - u2) / 2s
here,
u = 100m/s
s = 1m
v = 0
so,
a = (0 - 1002) / 2x1
thus,
a = -5000 m/s2
now,
in the second case
v = [u2 + 2as]1/2
here,
u = 100m/s
a = -5000 m/s2
and
s = 25cm = 0.25m
so,
v = [1002 + -(5000x0.25)]1/2
= [10000 - 1250]1/2
thus, emergent velocity will be
v = 93.541 m/s
a = (v2 - u2) / 2s
here,
u = 100m/s
s = 1m
v = 0
so,
a = (0 - 1002) / 2x1
thus,
a = -5000 m/s2
now,
in the second case
v = [u2 + 2as]1/2
here,
u = 100m/s
a = -5000 m/s2
and
s = 25cm = 0.25m
so,
v = [1002 + -(5000x0.25)]1/2
= [10000 - 1250]1/2
thus, emergent velocity will be
v = 93.541 m/s
Answered by
0
Answer:
follow me
follow me
follow me
Similar questions