Question

A bullet with muzzle velocity 10√10 ms is to be shot at a target 50 m away in the same horizontal line. The height above the target must the rifle to be aimed so that the bullet will hit the target

Answer 1

$here \: \:is \: \: your \: answer$


according to question,

↪Time taken by bullet to reach the target

T = Distance / Speed
= 50 / 10√10
= √2.5 seconds

↪Height above the target should be

$H \: = 0.5gT^2$

= 0.5 × 10 × (√2.5)^2
= 5 × 2.5
= 12.5 m

$Height \: above \: the \: target \: should \: be \: 12.5 \: m$



$hope \: it \: helps$

$\beta e \: brainly$

Answer 2

according to question,

↪Time taken by bullet to reach the target

T = Distance / Speed

= 50 / 10√10

= √2.5 seconds

↪Height above the target should be

H \: = 0.5gT^2H=0.5gT

2

= 0.5 × 10 × (√2.5)^2

= 5 × 2.5

= 12.5 m

Height \: above \: the \: target \: should \: be \: 12.5 \: mHeightabovethetargetshouldbe12.5m