A Bullock and a donkey wear carrying boxes on their backs. The the bullet complaint to the donkey that his load was too heavy. The donkey consoled him by saying,'If you give me one of your boxes, I would have double what you have and said if I gave you an of my boxes, we both would have an equal load'. How many boxes in each animal carrying?
Answers
Answered by
1
The mule was carrying 5 sacks and the donkey was carrying 7
sacks.
Let's assume that the mule was carrying M sacks and the
the donkey was carrying D sacks.
As the donkey told the mule, "If you gave me one of your
sacks I'd have double what you have."
D + 1 = 2 * (M-1)
D + 1 = 2M - 2
D = 2M - 3
The donkey also said, "If I give you one of my sacks we'd
have an even amount."
D - 1 = M + 1
D = M + 2
Comparing both the equations,
2M - 3 = M + 2
M = 5
Substituting M=5 in any of the above equation, we get D=7
VERIFICATION-
5 - 1 = 7 + 1/2
4 = 4
5 + 1 = 7 - 1
6 = 6
VERIFIED
Hence, the mule was carrying 5 sacks and the donkey was
carrying 7 sacks.
Answered by
0
Answer:
bullock has 2 boxes and donkey also has two boxes
Step-by-step explanation:
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