Question

A bungalow is sold by A to B, at a profit of 10% and by B to C, at a loss of 10%.
If C, pays Rs.9,80,100 for it, what did the bungalow cost A ?​

Answer 1

Answer:

Step-by-step explanation:

If B sells the Bungalow to C for ₹9,80,100 at a loss of 10%,

The cost at which B buys for A = x- (10/100 × x) = 980100

                                                   = 100x-10x/100 = 980100

                                           = 90x = 980100×100⇒x= 980100×100/90

                                           x=₹10,89,000

Therefore, B sells the bungalow to C for ₹10,89,000

The original cost of the bungalow with A= y + (10y/100) = x

                                                                   = 110y/100 = 1089000

                                               = 11y = 10890000 ⇒ y= 10890000/11

                                                                 y = ₹9,90,000

Therefore, the original cost of the bungalow with A is ₹9,90,000

Answer 2

Answer:-

Let the CP of the bungalow when it is with A be Rs. x.

Given:-

A sold it to B at a profit of 10%.

We know,

SP = CP × (100 + profit%) / 100

⟹ SP = x * (100 + 10) / 100

⟹ SP = 110x/100

⟹ SP = 11x/10

And also given that,

B sold it to C at a loss of 10%.

and , SP = Rs. 9,80,100.

Here,

The price at which the bungalow is sold to B will be the cost price.

We know,

CP = SP × (100/ 100 - loss%)

⟹ 11x/10 = 9,80,100 × (100/100 - 10)

⟹ x = 980100 × 10/11 × 100/90

⟹ x = Rs. 9,90,000

∴ The Initial price of the bungalow is Rs. 9,90,000.