A bungee jumper with a weight of 588 N leaps off a bridge. He is in free fall for a distance of 24.0 m before the cord begins to stretch. How much work, in kilo joules, does the force of gravity do on the jumper before the cord begins to stretch? Show all our work.
Answers
Answered by
9
Answer:
14.112 kilojoules
Explanation:
Work done = F*S
F= 588
S = 24
WORK DONE = 588*24=14112 joules
Answered by
0
Answer:
xk
Explanation:
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