A buoy in the ocean is observed from the top of a 40 meter high oil rig. the angle of depression from the top of the tower to the buoy is 6 degree. how far is the buoy from the base of the oil rig?
Answers
Answer:
A buoy in the ocean is observed from the top of a 40 meter high oil rig. the angle of depression from the top of the tower to the buoy is 6 degree. how far is the buoy from the base of the oil rig
Concept:
sinA= perpendicular/hypotenuse
cosA=base/hypotenuse
tanA=perpendicular/base
cotA=1/tanA=base/perpendicular
secA=1/cosA= hypotenuse/base
cosecA=1/sinA=hypotenuse/perpendicular
Given:
A buoy in the ocean is observed from the top of a 40 meter high oil rig. the angle of depression from the top of the tower to the buoy is 6 degree.
Find:
How far is the buoy from the base of the oil rig?
Solution:
AB=40m
Let C be the rig
So, ∠ACB =6
Since, a angle and perpendicular is give, we will use tan
tanC =AB/BC
⇒tan 6=40/BC
⇒0.105=40/BC
⇒BC=40/0.105
⇒BC=380.95m
Therefore, the distance between the base of the oil rig and bouy is 380.95m
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