a bus accelerate uniformly from 18 km/h to 36 km/h in 10second calculate the acceleration
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u= 18 km/h= 18*5/18= 5m/s
v= 36 km/h= 36*5/18= 10m/s
t= 10 seconds
a= ?
v= u+at
10= 5+ 10a
10-5 = 10a
5/10= a
a= 0.5 m/s²
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v= 36 km/h= 36*5/18= 10m/s
t= 10 seconds
a= ?
v= u+at
10= 5+ 10a
10-5 = 10a
5/10= a
a= 0.5 m/s²
Please rate the brainliest answer!!!!
Answered by
1
the acceleration is 0.5m/s^2 or 6.48 km/h^2.
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