Question

A bus accelerated uniform from 54km/h to 72km/h in 10s calcute accelertion in m/s and distance covered by bus

Answer 1

Answer:

Explanation:

u = 54 m/s

v = 72 m/s

t = 10 s

a = v-u /t

72 -54 /10

a = 1.8 m/s²

s = ut + 1/2 at²

s = 54 * 10 + 1/2 * 18 /10 * 10²

s = 540 + 90

s = 630 m

Answer 2

u=72×5/18=20m/s
v=54×5/18=15m/s
t=10s
I) a=v-u/t
=15-20/10
=-5/10
=-1/2
ii) s=ut+1/2at^2
=20×10+1/2×-1/2×100
=175m
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