a bus accelerates at 2m/s2 for first 10s after the start and retards at 1m/s2 for next 10secs. find the total distance covered by the bus.
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in first 10s
s1=u(10)+1/2(2)(10)^2=0+100=100m
for next 10seconds velocity v^2=0^2+2(2)100=400,v=√400=20
s2=20(10)-1/2(1)10^2=200-100=100
total=100+100=200.
s1=u(10)+1/2(2)(10)^2=0+100=100m
for next 10seconds velocity v^2=0^2+2(2)100=400,v=√400=20
s2=20(10)-1/2(1)10^2=200-100=100
total=100+100=200.
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