Question

a bus accelerates from 36km/hr to 72km/hr in 20 mins. Find the distance

Answer 1

Explanation:

Speed = Distance/Time

Therefore, Distance = Speed*Time

Average speed here = 72-36= 36 km/hr

= 16.6 m/min (Km/hr * 1000/60 for m/min)

Hence, distance = 16.6/20= 0.83 m (approx)

Answer 2

Explanation:

u= 36km/h=36×5÷18m/s

10 m /s.

v=72 km/h=20 m/s

time=20min=20×60=1200s

v=u+at

at=v-u

a=v-u/t

=20-10/1200

=10/1200m/s^2