Question

A bus accelerates from rest at the rate of 0.2 m/s2. What will be the velocity attained by it in 1 minute?

Answer 1

$\large\underline{\sf{\red{Given:-}}}$

$\dag\: \sf{Rate :- 0.2m/s^2}$

$\dag\: \sf{Time :- 1 min }$

$\dag\: \sf{Initial\: Velocity :- 0m/s}$

$\large\underline{\sf{\red{To Find:}}}$

$\sf{Velocity \:attained\: by\: it\: in\: 1\: minute}$

$\large\underline{\sf{\red{Solution :}}}$

Concept :

$\dashrightarrow\: \sf{Velocity:- Velocity\: is \:the\: rate\: of\: change\: of\: the}$

$\sf{position\: of \:an\: object}$

$\dashrightarrow\: \sf{Formula :- \large\ \frac{Displacement}{Time} }$

$\dashrightarrow\: \sf{It\: is \:a \:vector\: quantity.}$

$\dashrightarrow\: \sf{Its \:S.I. \:unit\: is \:m/s.}$

✴ $\sf{First \:equation \:of\: kinematics :}$

★ $\underline{\boxed{\sf{v=u+at}}}$

Where,

⇛ v denotes final velocity

⇛ u denotes initial velocity

⇛ a denotes acceleration

⇛ t denotes time

Conversion:

$\implies\: \sf{1\: minute = 60 sec}$

Calculation:

$\implies\: \sf{v=u+at}$

$\implies\: \sf{v=0+0.2\times 60}$

$\implies\: \underline{\boxed{\sf{v=12m/s}}}$

$\sf{Hence\:the\: velocity\:will\:be\:12m/s}$