A bus accelerates uniformly form 54 km/hr to 72 km/hr in 10 sec .Find acceleration and distance travelled?
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acceleration by v=u +at
54k/hr= 15m/s
72k/hr=20m/s
20=15 + 10a
-10a=-5
a=0.5 m/s
Distance by 2as=v2-u2
2X0.5s= (20)2 -( 15)2
s=400- 225
s=175m/s
54k/hr= 15m/s
72k/hr=20m/s
20=15 + 10a
-10a=-5
a=0.5 m/s
Distance by 2as=v2-u2
2X0.5s= (20)2 -( 15)2
s=400- 225
s=175m/s
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