Question

A bus accelerates uniformly
from 16km/h to 38km/h
in 8s. Calculate
(i) the acceleration
(ii) the distance Covered by the car in that time.
​

Answer 1

Step-by-step explanation:

Given,

u= 16km/h =4.5m/s

v=38km/h. = 10.5m/s

time=8s

acceleration=(v-u)/t

=10.5-4.5)/8

=6/8

=0.75 m/s^2

distance =ut+1/2at^2

=36+24

=60m.

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