Question

A bus accelerates uniformly from 18 kilometre per hour to 26 kilometre per hour in 10 seconds calculate the acceleration​

Answer 1

$\huge{\underline{\sf Solution:-}}$

Here First we have to convert Both units to m/s

Let's do

$\\ \tt{:}\longrightarrow 18km/h=18\times \dfrac{5}{18}$

$\\ \tt{:}\longrightarrow 5m/s$

$\\ \tt{:}\longrightarrow 26km/h=26\times \dfrac{5}{18}$

$\\ \tt{:}\longrightarrow \dfrac{130}{18}$

$\\ \tt{:}\longrightarrow 7m/s (approx)$

• Initial velocity=u=5m/s
• Final velocity=v=7m/s
• Time taken=t=10s

We know that

$\boxed{\sf Acceleration=\dfrac{v-u}{t}}$

$\\ \tt{:}\longrightarrow Acceleration=\dfrac{7-5}{10}$

$\\ \tt{:}\longrightarrow Acceleration=\dfrac{2}{10}$

$\\ \tt{:}\longrightarrow Acceleration=0.2ms^{-2}$