Question

A bus accelerates uniformly from 54 km/h to 72 km/h in 10 seconds Calculate
(i) acceleration in m/s2
(ii) distance covered by the bus in metres during this interval.

Answer 1

72×5÷18=20M/S

54×5÷18=15M/S

20-15/10=0.5 M/S^2

ii)

$v^{2} - u^{2} = 2as \\ 20^{2} - \: 15^{2} = 2 \times 1 \div 2 \times s \\ 400 - 225 = s \\ 175m = s$

Answer 2

Answer:

1sᴛ , ᴡᴇ ʜᴀᴠᴇ ᴛᴏ ᴄᴏɴᴠᴇʀᴛ ᴋᴍ/ʜʀ ɪɴᴛᴏ ᴍ/s

54*5/18 = 15ᴍ/s

72*5/18 = 20ᴍ/s

ᴜ = 15ᴍ/s

ᴠ = 72ᴍ/s

ᴛ = 10s

ᴀ= ?

s= ?

ɪɴ 1sᴛ ᴄᴀsᴇ , ᴡᴇ ᴀᴘᴘʟʏ ᴛʜᴇ ғᴏʀᴍᴜʟᴀ : ᴀ = ᴠ - ᴜ / ᴛ

ᴀ = 20ᴍ/s - 15ᴍ/s / 10s

ᴀ = 0.5ᴍ/s^2

ɪɴ 2ɴᴅ ᴄᴀsᴇ , ᴡᴇ ᴀᴘᴘʟʏ ᴛʜᴇ ғᴏʀᴍᴜʟᴀ : s = ᴜᴛ + 1/2ᴀᴛ^2

s = 15ᴍ/s*10s + 1/2*0.5ᴍ/s^2*(10s)^2

s = 150ᴍ + 1/2*0.5ᴍ/s^2*100s^2

s = 150ᴍ + 1/2 * 0.5ᴍ*100

s = 150ᴍ + 50/2ᴍ

s = 150ᴍ + 25ᴍ

s = 175ᴍ

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs.............