A bus accelerates uniformly from 54 km/h to 72 km/h in 10 seconds
Calculate:
(i) acceleration in m/s2.
(ii) distance covered by the bus in meters during this interval.
Answers
Answered by
0
Answer:
v
c
=54 km/h=
3600
54×1100
=15 m/s
v
f
=72 km/h=
3600
72×1000
=20 m/s
∴ Acceleration
t
v
f
−v
c
=
10
20−15
=0.5 m/s
2
Explanation:
Answered by
2
Answer:
i) 1.8 m/s²
ii) 630 m
Explanation:
Uniform acceloration means you use SUVAT equations.
s = displacement
u = initial velocity
v = final velocity
a = acceloration
t = time
i) v = u + at
substitute values in and solve for a:
72 = 54 + 10a
10 a = 18
a = 1.8
ii) v² = u² + 2as
subsitiute values in and solve for s:
72² = 54² + 3.6s
3.6s = 2268
s = 630
Similar questions