Question

 A bus accelerates uniformly from 54 km/h to 72 km/h in 10 seconds Calculate

       (i)  acceleration in m/s2

       (ii)  distance covered by the bus in metres during this interval.

Answer 1

Hey! ! !

Mate :-

Solution :-

To change km/h to m/s

54 km/h = 54×5/18

= 15 m/s

Nd 72 km/h

= 72 ×5/18

=20 m/s

:- As We know the

s = ut + 1/2at*2

:- u = 0

:- t = 10 sec

= o×10 + 1/2× 20 × 10 × 10

= 1000 m = 1 km

☆ ☆ ☆ Hop its helpful ☆ ☆ ☆

☆ Regards :- ♡♡《 Nitish kr singh 》♡♡

Answer 2

Given
u=54km/hrs
=15m/sec

v=72km/hr
=20m/sec

t=10sec

Since acceleration =v-u/t
=20-15/10
=5/10m/sec^2
=0.5 m/sec^2
Now,from 2nd equation of motion
s=ut+1/2at^2
=54×10+1/2×0.5×10×10
=540+1/4×100
=540+25m
=565m

Hope this helps u