a bus accelerates uniformly from 54 km per hour to 72 km per hour in 10 seconds calculate:(a) acceleration in metre per second square.(b) distance covered by the bus in m during this interval
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initial=>54*5/18=>15m/s (u)
final =>72*5/18=>20m/s(v)
time =>10 seconds
acceleration =>20-15/10 =>5/10=>0.5m/s^2
final =>72*5/18=>20m/s(v)
time =>10 seconds
acceleration =>20-15/10 =>5/10=>0.5m/s^2
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