Question

A bus accelerates uniformly from 54km/ h to 72 km/ h in 10 sec calculate acceleration in m/ s ² , distance covered by the bus in metres during this interval

Answer 1

Given

u =54km/h = 15m/s

v = 72km/h = 20m/s

t= 10s

Solution

a= (v-u) / t

a= (20-15 ) / 10

a = 0.5 m/s^2

s = ut + 0.5 × at^2

s= 15×10 + 0.5 × 0.5 × 100

s= 175 meters