A bus accelerates uniformly from 54km/hr to 72km/hr in 10 seconds.
1.distance covered by the bus in metres during this interval.
sarthak123456:
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a=v-u/t
72km/h=72×5/18=20m/s
54km/h=54×5/18=15m/s
a=2015/10
=5/10
a=0.5m/s^2
to find the distance to use the formula-
v^2=u^2+2as
v=72km/h
u=54km/h
20^2=15^2+2×0.5×5
400=225+1s
400-225=s
s=175m
so, distance=175m
hope this helps u☺
72km/h=72×5/18=20m/s
54km/h=54×5/18=15m/s
a=2015/10
=5/10
a=0.5m/s^2
to find the distance to use the formula-
v^2=u^2+2as
v=72km/h
u=54km/h
20^2=15^2+2×0.5×5
400=225+1s
400-225=s
s=175m
so, distance=175m
hope this helps u☺
I want distance travelled by bus according to the given information
ok
I gave u a also
ok
your q was half
a was not there
I gave because I have done this question
From where u find s in the equation
s is distance
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