Physics, asked by burmanlavanya6, 5 months ago

a bus accelerates uniformly from rest and acquires a speed of 72k/h in 20s . find the acceleration of the bus​

Answers

Answered by manjeetkaur1468
0

Answer:

V=u +at

v= 72km/h

72* 1000/3600

given - u = 0 , t=20sec

a= 72*1000/3600 *1/20

a=1.46

Answered by NightcoreWolfie
10

Provided Question

A bus accelerates uniformly from rest and acquires a speed of 72km/h in 20s . Find the acceleration of the bus.

How to solve?

Basically in this question, the initial velocity (u) of the bus is 0m/s as it started from rest and it acquires a speed of 72km/h which is its final velocity and time taken is 20s.

  • So we need to convert its final velocity to its standard form.
  • Then we'll calculate the acceleration according to the formula which is  \sf { a = \dfrac{v-u}{t} }

Required Solution

 {\underline {\large {\underline {\rm { Given: } }}}}

  • Initial velocity (u) = 0m/s [ As it started from rest. ]

  • Time taken (t) = 20s

  • Final velocity (v) = 72km/h

 \leadsto Converting to its SI unit:

To convert km/h to its SI unit, simply we'll multiply it by 5/18 and we'll get the answer.

 \sf { \implies \cancel{72} \times \dfrac{5}{\cancel{18}} }

 \sf { \implies 4 \times 5 }

 \sf { \implies 20m/s }  \purple{ \bigstar }

 {\underline {\large {\underline {\rm { To \: Calculate:} }}}}

  • acceleration (a)

 {\underline {\large {\underline {\rm { Calculation:} }}}}

We know that "acceleration is the rate of change in velocity over time".Therefore:

  • {\boxed {\huge {\bf {\pink { a =\dfrac{v-u}{t} }}}}}

Substituting values:

 \sf { \implies a =\dfrac{ 20-0}{20}}

 \sf { \implies a= \dfrac{ 20}{20}}

 \sf\red { \implies a = 1m/{s}^{2}}

Therefore,acceleration of the bus is  \sf { 1m/{s}^{2}}

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Some basic info

  • Acceleration is the rate of change is velocity over time.
  • It is a vector quantity.
  • SI unit of acceleration is  \sf { m/{s}^{2}} .
  • Formula :  \sf { a = \dfrac{v-u}{t} }

Three equations of motion:

  • {\boxed {\huge {\bf {\pink { v=u+at}}}}}
  • {\boxed {\huge {\bf {\pink { s =ut + \dfrac{1}{2}a{t}^{2}}}}}}
  • {\boxed {\huge {\bf {\pink { 2as ={v}^{2}-{u}^{2}}}}}}

Where,

  • v denotes final velocity.
  • u denotes initial velocity.
  • a denotes acceleration.
  • s denotes distance/displacement
  • t denotes time.

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