a bus accelerates uniformly from rest and acquires a speed of 72k/h in 20s . find the acceleration of the bus
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Answer:
V=u +at
v= 72km/h
72* 1000/3600
given - u = 0 , t=20sec
a= 72*1000/3600 *1/20
a=1.46
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★ Provided Question ★
A bus accelerates uniformly from rest and acquires a speed of 72km/h in 20s . Find the acceleration of the bus.
How to solve?
Basically in this question, the initial velocity (u) of the bus is 0m/s as it started from rest and it acquires a speed of 72km/h which is its final velocity and time taken is 20s.
- So we need to convert its final velocity to its standard form.
- Then we'll calculate the acceleration according to the formula which is
★ Required Solution ★
- Initial velocity (u) = 0m/s [ As it started from rest. ]
- Time taken (t) = 20s
- Final velocity (v) = 72km/h
Converting to its SI unit:
To convert km/h to its SI unit, simply we'll multiply it by 5/18 and we'll get the answer.
- acceleration (a)
We know that "acceleration is the rate of change in velocity over time".Therefore:
Substituting values:
Therefore,acceleration of the bus is
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★ Some basic info ★
- Acceleration is the rate of change is velocity over time.
- It is a vector quantity.
- SI unit of acceleration is .
- Formula :
Three equations of motion:
Where,
- v denotes final velocity.
- u denotes initial velocity.
- a denotes acceleration.
- s denotes distance/displacement
- t denotes time.
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