Question

A bus accelerates uniformly from rest and acquires a speed of 36kmph in 12s. The
acceleration is

Answer 1

Answer:

Initial speed=u=0m/s

final speed=v=36000/(60×60)=10m/s

a=(v-u)/2=(10-0)/12=5/6m/s^2

Answer 2

Answer:

v = u + at

here u = 0 m /s

v = 36 kmph = 36 × (5 /18) = 10 m /s

t = 12 s

therefore

10 = 0 + a × 12

10 = 12a

a = 10 ÷ 12

a= 0.83 m/s^2