Question

A bus accelerates uniformly from rest and axciqures a speed of 75 kmph in 20 sec the acceleration of business is

Answer 1

Solution :

⏭ Given:

✏ Initial speed of bus = 0

✏ Final speed of bus = 75kmph

✏ Time interval = 20s

⏭ To Find:

✏ Acceleration of bus

⏭ Formula:

✏ First equation of kinematics is given by

$\star \: \underline{ \boxed{ \bold{ \sf{ \pink{ \large{v = u + at}}}}}} \: \star$

⏭ Terms indication:

✏ v denotes final speed

✏ u denotes initial speed

✏ a denotes acceleration

✏ t denotes time interval

⏭ Conversation:

✏ 75kmph = 20.83mps

⏭ Calculation:

$\implies \sf \: 20.83 = 0 +( a \times 20) \\ \\ \implies \sf \: 20.83 = 20a \\ \\ \implies \underline{ \boxed{ \bold{ \sf{ \purple{ \large{a = 1.04 \: m {s}^{ - 2}}}}}}} \: \gray{ \bigstar}$

⏭ Additional information:

• Acceleration, displacement and velocity are vector quantities.
• Distance and speed are scalar quantities.

Answer 2

$\huge \mathtt{ \fbox{Solution :)}}$

Given ,

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 75 km/hr or 20.8 m/s
• Time (t) = 20 sec

We know that , the rate of change of velocity of body is called acceleration of the body

$\mathtt{ \large \fbox{Acceleration \: (a)= \frac{v - u}{t} }}$

Thus ,

a = (20.8 - 0)/20

a = 208/20

a = 1.4 m/s²

Hence , the acceleration of the body is 1.04 m/s²

______________ Keep Smiling ☺