Physics, asked by sagarspatel9930, 2 months ago

A bus acceleration uniformly from rest and acquires a speed of 72 km ph 10 sec find the acceleration

Answers

Answered by MystícPhoeníx
117

Given:-

  • Initial velocity ,u = 0m/s
  • Final velocity ,v = 72km/h
  • Time taken ,t = 10s

To Find:-

  • Acceleration ,a

Solution:-

According to the Question

It is given that bus acceleration uniformly from rest and acquires a speed of 72 km/h 10 sec.

we have to calculate the acceleration of the bus .

Firstly we change the speed into m/s.

v = 72 × 5/18

v = 4×5

v = 20m/s

Now, we know that acceleration is defined as the rate of change in velocity.

  • a = v-u/t

where,

  • v is the final velocity
  • a is the acceleration
  • u is the initial velocity
  • t is the time taken

Substitute the value we get

\longrightarrow a = 20-0/10

\longrightarrow a = 20/10

\longrightarrow a = 2m/

  • Hence, the acceleration of the bus is 2m/.

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Answered by Anonymous
78

Answer:

Given :-

  • A bus acceleration uniformly from rest and acquires a speed of 72 km/h in 10 seconds.

To Find :-

  • What is the acceleration.

Formula Used :-

\clubsuit First Equation Of Motion Formula :

\mapsto \sf\boxed{\bold{\pink{v =\: u + at}}}

where,

  • v = Final Velocity
  • u = Initial Velocity
  • a = Acceleration
  • t = Time

Solution :-

First, we have to convert final velocity (v) km/h into m/s :

\implies \sf Final\: Velocity =\: 72\: km/h

\implies \sf Final\: Velocity =\: 72 \times \dfrac{5}{18}\: m/s\: \: \bigg\lgroup \sf\bold{\pink{1\: km/h =\: \dfrac{5}{18}\: m/s}}\bigg\rgroup\\

\implies \sf Final\: Velocity=\: \dfrac{360}{18}\: m/s

\implies \sf \bold{\purple{Final\: Velocity =\: 20\: m/s}}

Given :

\bigstar\: \: \rm{\bold{Initial\: Velocity (u) =\: 0\: m/s}}

\bigstar\: \: \rm{\bold{Final\: Velocity (v) =\: 20\: m/s}}

\bigstar\: \: \rm{\bold{Time (t) =\: 10\: seconds}}

According to the question by using the formula we get ,

\longrightarrow \sf 20 =\: 0 + a(10)

\longrightarrow \sf 20 =\: 0 + 10a

\longrightarrow \sf 20 - 0 =\: 10a

\longrightarrow \sf 20 =\: 10a

\longrightarrow \sf \dfrac{2\cancel{0}}{1\cancel{0}} =\: a

\longrightarrow \sf \dfrac{2}{1} =\: a

\longrightarrow \sf 2 =\: a

\longrightarrow \sf\bold{\red{a =\: 2\: m/s^2}}

\therefore The acceleration of the bus is 2 m/.

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